Lecture 1
What are real numbers?
There are two methods to construct real numbers:
-
Dedekind (1831-1916)
Dedekind cut: If $x \in A^-, y \in A^+ \Rightarrow x \lt y,$ then the cut $(A^-, A^+)$ determines a real number. But elementary arithmetic is cumbersome; think about $(A^-, A^+) + (B^-, B^+).$ -
Cantor (1845-1918)
Define real numbers with sequences, which makes elementary arithmetic easier. If $X = \{ x_n \in \mathbb{Q} \}$ and $Y = \{ y_n \in \mathbb{Q} \}$ converge to the same number, say, $\sqrt{2},$ then they should be “equal”.
Def. $X \leq Y$ if each upper bound of $Y$ is also an upper bound of $X.$
Remark:
- Reflexive: $X \leq X.$
- Transitive: $X \leq Y$ and $Y \leq Z \Rightarrow X \leq Z.$
Let $S$ be the set of all bounded, non-decreasing, and rational sequences. Then $\langle S, \leq \rangle$ is an ordered set.
Let $X \sim Y$ denote $X \geq Y$ and $X \leq Y.$ Then $S$ can be split into equivalent classes. The set of all such equivalent classes is called the real numbers.
Exercise:
- Prove the equivalent classes defined by $\sim$ have good properties:
- $X \sim X$
- $X \sim Y \Rightarrow Y \sim X$
- $X \sim Y$ and $Y \sim Z \Rightarrow X \sim Z$
- Prove elementary arithmetic has good properties:
- Existence of the $\mathbf{0}$ element
- Commutativity of addition and multiplication
- Associativity of addition and multiplication
- etc.
-
Prove law of trichotomy
Def. (Addition)
Let $\xi, \eta \in \mathbb{R},$ that is,
$\xi \sim X = \{ x_1, \dotso \}$ and $\eta \sim Y = \{ y_1, \dotso \}$
for some sequence $X$ and $Y.$
Define
$\xi + \eta \stackrel{\small{\text{def}}}{\sim} \{ x_1 + y_1, \dotso \}.$
Remark:
- The $\mathbf{0} = \{ 0, \dotso \}$ element exists
- Commutativity: $\xi + \eta = \eta + \xi$
- Associativity: $(\xi + \eta) + \zeta = \xi + (\eta + \zeta)$
- Existence of additive inverse: $\forall \xi \exists \eta, \xi + \eta = 0$ (Note: $Y = \{ -x_n \}$ is not non-decreasing.)
- Total order; thus $\xi \gt \eta \Rightarrow \xi + \zeta \gt \eta + \zeta.$ Note: If $\xi = \{ x_n \} \lt \eta = \{ y_n \},$ then $\exists r \in \mathbb{Q}$ such that $r$ is an upper bound of $\xi$ but not an upper bound of $\eta.$ That is, $\exists N$ such that $r \lt y_n$ for all $n \gt N.$ Thus $\exists N$ such that $x_k \lt y_n$ for all $k$ and for all $n \gt N.$
Proof. (Existence of additive inverse)
Idea: Find a non-increasing sequence $\{ y_n \} \to \xi,$
then $\{ -y_n \}$ is non-decreasing and is the additive inverse of $\{ x_n \}.$
Let $r \in \mathbb{Q}$ be an upper bound $\{ x_n \}.$
Make $y_1 = r,$ and use bisection method to compute $y_2.$
Let $m = \frac{x_1 + y_1}{2}:$
- If $m$ is an upper bound of $\xi,$ then make $y_2 = m.$
- Otherwise make $y_2 = y_1.$ Pick some $x_i \gt m$ and apply bisection method on $(x_i, y_2).$